Question

Find the equation of the perpendicular bisector of line segment joining A(4, 2) and B(-3, -5)

Answer 1

Find the equation for the right bisector of the line segment joining the points A(1,0) and B(2,3).
------
The mid-point is ((1+2)/2,(0+3)/2) = (3/2 , 3/2)
----
The line thru AB is 3/1 = 3
-----
The slope of the bisector must be -1/3
------------------------------------------

Form: y = mx+b
0 = (-1/3)1+b
b = 1/3
---
Equation of perpendicular bisector is y = (-1/3)x+(1/3)
========================================================
Cheers,
Kunal(007)
============

Answer 2

The objective is to determine the graph is a vertical, horizontal or oblique line.

A vertical line has an equation of the form for some number .

A horizontal line has an equation of the form for some number .

An oblique line is a line that is neither vertical line nor horizontal line. The graph of equation is .

a. The equation is .

The above equation is in the form of for the number 0.

So, the graph of the equation is a vertical line.

If useful plz mark me as brainiest