Question

find the equation of the perpendicular bisector of the straight line segment joining hte points A(-2,4) and B(6,-8)​

Answer 1

Step-by-step explanation:

m=y2-y1/x2-x1

m=-8-4/6+2

m=-12/8

m=-3/2

mid point of the line

(x1+x2/2),(y1+y2/2)

(-2+6/2),(4-8/2)

(2,-2)

equation of straighte line

y-y1=m(x-x1)

y+2=-3/2(x-2)

2(y+2)=-3x+6

2y+4=-3x+6

2y+3x-2=0