Question

find the equation of the perpendicular bisector of the line segment joining the points A(1,1) and B(2,3)

Answer 1

let mid point of AB be M.
coordinates of M;
(1*1+2*1/2), (1*1+3*1/2);
(1+2/2),(1+3/2);
(3/2,4/2);
(3/2,2);
then equation is,
slope= 3-1/2-1;
= 2/1=2;
then,
m(3/2-x) = (2-y);
2(3-2x/2)=(2-y);
2(3-2x)=2(2-y);
6-4x=4-2y
so equation is,
4x-2y+4-6=0;
4x-2y-2=0;
4x-2y=2...
hope answer helps you