find the equation of the perpendicular bisector of the line segment joining the points A(3,6) and B(-3,4) . Also find the points where it meets the x-axis ? meritnation
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first find the mid point of these points and slope of AB and the use M1 *M2 =-1 and then write the eqn of line in slope and point form
hope hint will help u
hope hint will help u
Anonymous:
slope= (Y2-Y1)/(X2-X1)
than slope of line AB = 6-4/3+3
then slope=1/3
and slope of perpendicular bisector = -3
since m1m2=-1
mid point of AB=(0,1)
now line of the eqn y-1/x=-3
y+3x=1
now put y=0 than x=1/3
hope it will help you
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