Question

find the equation of the perpendicular bisector of the side BC of the triangle with the vertices A(0,6) B(-2,2) and C(4,2)

Answer 1

Answer:

Equation is y=2

Step-by-step explanation:

Given Vertices are A(0,6), B(-2,2) and C(4,2)

Mid point of Line BC shall be

M (a,b) ={ (-2+4)/2, (2+2)/2}

here a= (-2+4)/2= 1

and b= (2+2)/2=2

Mid point M(1,2)

slope m1 shall be (y2-y1)/(x2-x1)

and m2 , perpendicular to the line

m2= -1/m1

Here m1

= (2-2)/4+2)

=0/6

= 0

Equation shall be y-b=m2 (x-a)

here m1=0 therefore, y-2=0

y=2