Find the equation of the plane
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Dear Student:
Given: A=(1,3,5)
P =(3,-2,1)
AP direction is normal direction of plane.
So, AP=P-A=(3-1,-2-3,1-5)
=(2,-5,-4)
So,equation of the plane:
(1,3,5)+k(2,-5,-4)
Where k∈R
Hope it helps
Thanks
With Regards
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In the attachment I have answered this problem.
The solution is simple and easy to understand.
See the attachment for detailed solution.
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