Question

Find the equation of the plane parallel to the plane x + y + z = 5 , at a distance of 2 Q. units from the point (2,3,5).​

Answer 1

Answer:

Let an equation of a plane parallel to the plane x−2y+2z−5=0 be x−2y+2z+k=0...(i)

Perpendicular distance from O(0,0,0) to (1) is 1

1+4+4

∣k∣

=1

⇒∣k∣=3

⇒k=+3or−3

∴x−2y+2z−3=0

Step-by-step explanation:

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