Question

Find the equation of the plane passing through the point(-2,1,3) and having (3,-5,4)as direction ratios of its normal
​

Answer 1

Answer:

equation of plane is 3x−5y+4z=1

Step-by-step explanation:

This plane pass through(−2,1,3) so the point will satisfy the equation

                          3(−2)−5(1)+4(3)=c

                            c=1