Question

find the equation of the plane that contains the point (1,-2,3) and is parallel to the plane z=2x+3y-4​

Answer 1

Answer:

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Step-by-step explanation:

0hcei01g0igcie1u0f1d0uoqhzohxwohwgcwohwxhxohxxowhxowhxoqbxqohdo1hd1obd1pbd1pbcwocwobfwohdwohcowcgowhxwohxwphxwpxoxhpwhxwphxwphxqphxqphdqpxqpsh1psvowbxpqbxqphxqphxq

Answer 2

Equation of plane parallel to 2x+3y−4z=0 is given by,

2x+3y−4z+λ=0

Also it passes through (1,2,3)

⇒2(1)+3(2)−4(3)+λ=0⇒λ=4

Hence, required plane is

2x+3y−4z+4=0