Question

Find the equation of the plane through (3, 4, 5
and parallel to the plane 2x + 3y - 2=0.​

Answer 1

Step-by-step explanation:

Equation of plane parallel to 2x+3y−4z=0 is given by,

2x+3y−4z+λ=0

Also it passes through (1,2,3)

⇒2(1)+3(2)−4(3)+λ=0⇒λ=4

Hence, required plane is

2x+3y−4z+4=0

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