Find the equation of the plane through (3, 4, 5) and parallel to the plane 2x 3y z 0 .
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Answer:
Equation of plane parallel to 2x+3y−4z=0 is given by,
2x+3y−4z+λ=0
Also it passes through (1,2,3)
⇒2(1)+3(2)−4(3)+λ=0⇒λ=4
Hence, required plane is
2x+3y−4z+4=0
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