Question

find the equation of the plane through the intersection of the planes 3x-y+2z=0 and X+y+z-2=0and the point (2,2,1)​

Answer 1

Step-by-step explanation:

the plane is given by

u+wv = 0

3x - y + 2z + w(x + y + z - 2) = 0

since the plane contains that point it must satisfy the equation

6-2+2 + w(2+2+1 - 2) =0

6 + w(3) = 0

w= -2

ao equation is

3x-y+2z -2(x+y+z-2) =0

hope it helps

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