Question

Find the equation of the plane through the line of intersection of the planes 3x + 2y + 3 = 0, 2x + y – z + 2 = 0 and parallel to x + y + z = 2​

Answer 1

Answer:

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Answer 2

Answer:

The given planes are 2x + y - z - 3 = 0 …(i) and 5x - 3y + 4z + 9 = 0 …(ii) The equation of the plane passing through the line of intersection of (i) and (ii) is given by It is given that plane (iii) is parallel to x-1/2=y-3/4=z-5/5. => Normal of (iii) is perpendicular to given line. Putting the value of λ in (iii), we get the required plane. Read more on Sarthaks.com - https://www.sarthaks.com/57894/find-the-equation-of-the-plane-passing-through-the-line-of-intersection-of-the-planes-2x-y-z