Question

find the equation of the plane with intercepts 2,3and5 on the x,y,z - axis respectively.

Answer 1

Answer:

$\displaystyle \sf \longrightarrow \frac{x}{2} +\frac{y}{3} +\frac{z}{5} =1$

Step-by-step explanation:

Given :

x , y and z intercept are 2 , 3 and 5

We are asked to find equation of plane :

We know :

$\displaystyle \sf \frac{x}{a} +\frac{y}{b} +\frac{z}{c} =1$

where a , b and c represents intercept on x , y and z axis!

Therefore values of intercept as :

a = 2

b = 3

c = 5

Putting values in equation we get :

$\displaystyle \sf \longrightarrow \boxed{ \frac{x}{2} +\frac{y}{3} +\frac{z}{5} =1 }$

Hence we get required answer!