Question

Find the equation of the right bisector of the line segment joining the points A(3,-4) and B(5,-6).
pls ans fast

Answer 1

The end points of the line segment are A(3,4) and B(−1,2)

Hence the midpoint of the line AB is (

3−1

2

 

,

4+2

2

 

)

=(1,3)

Now the slope of the line is

m1=

2−4

−1−3

=

−2

−4

=

1

2

 

Hence the slope of the perpendicular will be

m2=−

1

(12)=−2

∴ Equation of the line passing through (1,3) and slope -2 is

(y−3)=−2(x−1)

(i.e., ) (y−3)=−2x+2

⇒2x+y=5

Hence the required equation of the line is 2x+y=5