Question

Find the equation of the right bisector of the line segment joining the points A(1, 1) and B (2, 3). in of the line​

Answer 1

Answer:

Let the points be A(1,1) and B(2,3)

Slope of AB=

2−1

3−1

=2

Product of slope of a line and its perpendicular is −1

⇒ Slope of perpendicular =−

2

1

Mid point of AB is

(

2

1+2

,

2

1+3

)

(

2

3

,2)

So the equation of perpendicular is

y−2=−

2

1

(x−

2

3

)

4y−8=−(2x−3)

2x+4y=11

2x+4y−11=0

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