Question

find the equation of the scale parallel to the line 2x+3y+7=0 & passing through the point (5, 3).​

Answer 1

Answer:

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Answer 2

Given :

Equation of the Parallel line  $2x+3y+7=0$

Points passing through $(5,3)$

To Find :

parallel line of $2x+3y+7=0$

Solution :

Equation of the straight line, parallel to $2x+3y+7=0$ is $2x+3y+k=0$ , since it passes through the point $(5,3)$  which is $(x,y)$

$\implies 2x+3y+k=0$

$\implies 2(5)+3(3)+k=0$

$\implies 19+k=0$

$\implies k=-17$

Therefore, equation of the required straight line is $2x+3y-17=0$

Explanation :

The equation of all lines $\text{\color{deeppink}{parallel to the line ax+by+c=0}}$ can be put in the form $\text{\color{deeppink}{ax+by+c=0}}$ for diffrent values of k.

(NOTE : In parallel lines there will be change in constant terms only. )