Question

find the equation of the set of points which are equidistant from the points (1,2,3) and (3,2,-1).

Answer 1

any point on the plane (x, y, z)

(x-1)²+(y-2)²+(z-3)²=(x-3)²+(y-2)²+(z+1)²
-2x+1-4y+4+-6z+9=-6x+9-4y+4+2z+1 (cancelling x², y², z² both sides)
4x-8z=0..... 

Answer 2

Here's ur answer

Hope it helps

#BAL