find the equation of the set of the points which are equal distance from the points a(1,-2,5) & b(0,4,-1)
Answers
Answered by
1
Answer:
2x-12y+12z-13=0
Step-by-step explanation:
let P(x,y) be the point
which is equidistant from points A and B
so
PA=PB
square on both sides
PA²=PB²
now
distance = √[(x2-x1)² +(y2-y1)² +(z2-z1)²]
so using this
PA² = PB²
that gives
(x-1)²+(y+2)²+(z-5)² = (x-0)²+(y-4)²+(z+1)²
x²+1-2x+y²+4+4y+z²+25-10z = x²+y²+16-8y+z²+1+2z
on simplifying
-2x+12y-12z+13=0
2x-12y+12z-13=0
Similar questions