Question

Find the equation of the sides of a triangle whose vertices are (1,4) , (2,-3) , (-1,-2)​

Answer 1

Answer:

find the area of the triangle whose vertices are A(1,2,3),B(2,3,1),C(3,1,2) by vector method

Answer 2

Answer:

(1,4) (2,-3) (-1,-2)

first we have to calculate the slope of each equation:

m1 = y2-y1/x2-x1

     = -3-4/2-1

     = -7

m2= -2+3/-1-2

    = 1/-3

m3 = 4+2/1+1

     = 3

now for the equations:

y-y1=m1(x-x1)

y-4= -7(x-1)

y-4 = -7x+7

7x+y-11=0

y-y2=m2(x-x2)

y+3 = 1/-3 (x-2)

-3y-9=x-2

x+3y+7=0

y-y3=m3(x-x3)

y+2=3(x+1)

y+2=3x+3

3x-y+1=0

Therefore the equations are:-

7x+y-11=0

x+3y+7=0

3x-y+1=0