Question

find the equation of the sides of an equilateral triangle whose vertex is(1, 2) and base is y =0​

Answer 1

Answer:

Draw a picture! The base is the y axis and the height is 2. The equation of a straight line is:

slope=m=ΔyΔx=(y−yp)/(x−xp)

Where (xp,yp) are the coordinates of a point on the line. Take the top vertex as that point for the two sides and solve for y :

y=mx+2+m

The slope of the left side is:

m=tan60o=3–√

So the equation of the left line is:

y=x3–√+2+3–√

The slope of the right side is: −3–√

So the equation of the right line is:

y=−x3–√+2−3–√

The equation of the base is of course:

y=0

Step-by-step explanation:

PLEASE MARK ME AS THE BRAINLIEST