Question

Find the equation of the sphere passes through the points (1,-4,3), (1,-2,2), (1,-3,0) and whose centre lies on the plane x+y+z =0

Answer 1

Answer:

sorry I dont know the answer

Answer 2

Answer:

Correct option is

B. (x−1)2+(y+3)2+(z−2)2=4

Step-by-step explanation:

(h−1)2+(k+3)2+(l−4)2=(h−1)2+(k+5)2+(l−2)2−−−(i)

∴(h−1)2+(k+3)2+(l−4)2=(h−1)2+(k+3)2+l2−−−(ii)

From equation (ii), l=2 

putting l=2 in (i) and solving, k=−3 

h+k+l=0 ∴h=1 and 

radius=(1−1)2+(−3+3)2+22

equation of sphere:(x−1)2+(y+3)2+(z−2)2=4