Question

find the equation of the straight line containing the point(3,2) and making positive equal interceps on axes​

Answer 1

X/a + y/b =1

X/a +y/a =1. (a=b)

X+y/a =1

X+y=a

(X,y) =(3,2)

3+2=a

a=5

substitute a=5 in Intercept form

X/5 + Y/5=1

X+y/5=1

X+Y=1(5)

X+Y=5

X+Y-5=0