find the equation of the straight line containing the point (3,2) and making positive equal intercept on axes
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the equation is x+y-5=0
let the intercepts be a and b.
given,
a=b
(x,y) = (3,2)
x/a+y/b=1
x+y/a=1
3+2/a=1
a=5
thus, the equation is x + y - 5 =0
plz brainlist the answer
let the intercepts be a and b.
given,
a=b
(x,y) = (3,2)
x/a+y/b=1
x+y/a=1
3+2/a=1
a=5
thus, the equation is x + y - 5 =0
plz brainlist the answer
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