Question

find the equation of the straight line joining (- 2, 3 - 6p) to (- 2 + 2p,3)
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*Only the answer...any other things will be reported*
***WARNING***
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Answer 1

Answer:

Answer:find the equation of the straight line joining (- 2, 3 - 6p) to (- 2 + 2p,3)

Answer:find the equation of the straight line joining (- 2, 3 - 6p) to (- 2 + 2p,3) *Any spam will be reported*

Answer:find the equation of the straight line joining (- 2, 3 - 6p) to (- 2 + 2p,3) *Any spam will be reported**Only the answer...any other things will be reported*

Answer:find the equation of the straight line joining (- 2, 3 - 6p) to (- 2 + 2p,3) *Any spam will be reported**Only the answer...any other things will be reported****WARNING***

Answer:find the equation of the straight line joining (- 2, 3 - 6p) to (- 2 + 2p,3) *Any spam will be reported**Only the answer...any other things will be reported****WARNING***

Answer:find the equation of the straight line joining (- 2, 3 - 6p) to (- 2 + 2p,3) *Any spam will be reported**Only the answer...any other things will be reported****WARNING***

Answer 2

Answer:

$y = 3x +9 - 6p$

Step-by-step explanation:

First, find the slope. The coordinates are $(-2, 3-6p) (-2+ 2p, 3)$. We bracket the expressions.

${\frac{y_{2} -y_{1} }{x_{2 }-x_{1} } }$

$\frac{3-(3-6p)}{-2+2p - (-2)}$

= $\frac{6p}{2p} = 3$

Now, insert the slope and any one of the coordinates to the slope-intercept form of an equation of a line. We are solving for the constant $c$ ( or $b$). I chose the second coordinate ( -2 +2p , 3).

$y= mx + c\\\\3= 3 ( -2 + 2p) + c\\= 3 = -6 + 6p + c\\= 9 = 6p + c\\= 9 - 6p = c$

Tadaa! We've found the constant! Now we'll substitute it into the slope-intercept form:

$y= mx + c\\y = 3x + 9 - 6p$

Note that we left p there as the question didn't ask us to solve p just the equation of the line.

Hope it helps!