Question

find the equation of the straight line parallel to 2x-3x-5=0 and passing through (4,5).

Answer 1

•αnswer•

Step-by-step explanation:

The equation of a line perpendicular to 3x + 2y + 5 = 0 is 2x - 3y + λ = 0 .........(i)

This passes through the point (3, 4)

∴3×2−3×4+λ=0⇒λ=6

Putting λ=6 in (i) we get 2x−3y+6=0 which is the required equation.