Question

Find the equation of the straight line parallel to the line 3x+4y=7 and passing through the point of intersection of the lines x-2y-3=0 and x+3y-6=0

Answer 1

Answer:

3x+4y +0=7

x - 2y -3 =0

× + 3y -6=0

Ans= 5x-y+9=7

Answer 2

Step-by-step explanation:

so the final answer is 3x+4y-15=0