Question

find the equation of the straight line passing through (-2;4)and making non zero intercepts whose sum Is zero
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Answer 1

$\mathtt{\huge{ \fbox{SOLUTION :}}}$

Given , The sum x intercept and y intercept is zero , so ,

b + a = 0

b = - a

We know that , the point intercept form is given by

$\large \star \sf \: \fbox{ \frac{x}{a} + \frac{y}{b} = 1 }$

Thus ,

$\sf \mapsto \frac{x}{a} - \frac{y}{a} = 1 \\ \\ \sf \mapsto x - y = a$

Since , the line is passing through the point (-2,4) , So

$\sf \mapsto - 2 - 4 = a \\ \\ \sf \mapsto a = - 6$

On substituting a = -6 in equation (i) , we get

x - y = - 6

Hence , x - y = - 6 is the required equation of line