Question

find the equation of the straight line passing through(3,-2)and making an angle of 60° with the positive direction of y-axis​

Answer 1

Answer:

√3x - y - 3√3 - 2 = 0

Step-by-step explanation:

$m = \tan( \alpha )$

$m = \tan( {60}^{0} )$

m =√3

equation of a line passing through a point and slope m is (y-y1) =m(x-x1)

equation of a line passing through a point(3, -2)and slope m =√3 is (y+2) =√3(x-3)

=> √3x - y - 3√3 - 2 = 0