find the equation of the straight line passing through the origin and the point of intersection of the lines x + 2y = 7 and x - y = 4
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first we find point of intersection
x+2y=7
x-y=4 solve it
x= 5, y=1
point (5,1) and (0,0) form line
slope of line =(0-1)/(0-5)=1/5
now equation of line
(y-0)=1/5 (x-0)
5y=x
hence x-5y=0 is equation of line
x+2y=7
x-y=4 solve it
x= 5, y=1
point (5,1) and (0,0) form line
slope of line =(0-1)/(0-5)=1/5
now equation of line
(y-0)=1/5 (x-0)
5y=x
hence x-5y=0 is equation of line
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