find the equation of the straight line passing through the point (4,5)and perpendicular to the line 2x+5y=3
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Step-by-step explanation:
2x+5y=3
slope is -a/b
-2/5. (slope ans)
(m)x-x1=y-y1
-2/5(x-2)=y-5
-2x+4=5y-25
2x+5y+29=0. (EQ 1)
m1xm2=-1
m2=-1/-2/5
m2=5/2
H.P
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