Question

Find the equation of the straight line passing through the point (0, 2)
which is perpendicular to the line
y = 1/4x + 5​

Answer 1

Answer:

4x+y-2=0

Step-by-step explanation:

The slope of line : y=1/4x+5 is in the form y=mx+c

Here,slope=1/4

Hence the slope of the line m perpendicular to the given line : y =1/4x+5 is

m=-4

Now the equation of the line passing through the poins ( x1, y1 ) = (0,2) & and having slope m= -4 is

y - y1 = m(x - x1)

Here,

y-2=-4( x - 0)

y-2=-4x

4x+y-2=0