Question

Find the equation of the straight line passing through the origin and also through the point of intersection
of the lines 2x - y + 5 = 0 and x + y + 1 = 0.​

Answer 1

Step-by-step explanation:

2x-y+5=0

2x-y=-5

X-y=-5/2

X+y+1=0

X+y=-1

Answer 2

Step-by-step explanation:

Given lines are

L1=2x-y+5= 0

L2=x+y+1=0

Equation of any line passing through the point of intersection of the lines L1=0 and L2=0 is L1+KL2 =0

==> ( 2x-y+5) +K (x+y+1) =0 -------(1)

The line is passing through O(0,0) ==> 5+k=0 ==>K=-5

substituting in (1), equation OA is (x-y+5) -5 (x+y+1)=0

===> 2x-y+5-5y-5=0

===> -3x-6y=0 ==> X+2y =0 // ans