Question

find the equation of the straight line passing through the point (3,2) and slope -2​

Answer 1

Answer:

it is a 34 yday 2=9 thank you

Answer 2

Given :

• Point = (3 , 2)
• Slope = -2

To Find :

• Equation of the straight line

Solution :

The equation of a straight line passing through the point (x₁ , y₁) and having slope m is given by ,

$\\ \star \: \boxed{\purple{\sf{(y - y_1) = m(x - x_1)}}}$

By comparing the data we have with the formulae ,

• x₁ = 3 , y₁ = 2
• m = -2

$\\ : \implies \sf \: (y - 2) = - 2(x - 3)$

$\\ : \implies \sf \: y - 2 = - 2x + 6$

$\\ : \implies \sf \: y - 2 + 2x - 6 = 0$

$\\ : \implies{\boxed{\pink{ \sf {2x + y - 8 = 0}}}} \: \bigstar$

Hence , The equation of the straight line passing through (3,2) and having slope -2 is 2x + y - 8 = 0.