Question

find the equation of the straight line passing through the point
(4,-3) and perpendicular to the line passing through the points
(1,1)
and (2,3)​

Answer 1

Answer:

Slope of line whose two points are given is

m=

2−1

3−1

=2

This is Perpendicular to required line

So, Slope of required line is

2

−1

Hence, Equation is y−(−3)=

2

−1

(x−4)⇒2y+6=−x+4⇒x+2y+2=0

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

Answer

Slope of line whose two points are given is

m=

2−1

3−1

=2

This is Perpendicular to required line

So, Slope of required line is

2

−1

Hence, Equation is y−(−3)=

2

−1

(x−4)⇒2y+6=−x+4⇒x+2y+2=0

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