find the equation of the straight line passing through the origin and perpendicular to 3x+2y+4=0
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3y - 2x = 0 is the equation of line perpendicular to 3x+ 2y +4=0
Slope of given line: y = -3/2 x - 4 = 0
Slope of perpendicular line = - (-2/3)
= 2/3
Equation of line: y = mx + c
Since line passes through origin, c = 0
Hence y = 2/3 x + c
Or 3y = 2x + 0
Or 3y - 2x =0
Slope of given line: y = -3/2 x - 4 = 0
Slope of perpendicular line = - (-2/3)
= 2/3
Equation of line: y = mx + c
Since line passes through origin, c = 0
Hence y = 2/3 x + c
Or 3y = 2x + 0
Or 3y - 2x =0
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