Question

Find the equation of the straight line passing through the point (2, 1) and through the point of intersection of the lines x + 2y = 3 and 2x – 3y= 4.​

Answer 1

Answer:

I don't know

Step-by-step explanation:

sorry for this

Answer 2

Answer:

The equation of any straight line passing through the intersection of the lines

x + 2y = 3 and 2x − 3y − 4 = 0  is written as λ(x + 2y − 3) + (2x − 3y − 4) = 0 ..

(1) Since the line passes through the point (2, 0),

we have  λ(2 + 0 − 3) + (4 − 0 − 4) = 0  That is, λ = 0.

Now substituting this value of λ in E. (1), we get  2x − 3y − 4 = 0

which is the equation of the given line.

Hope it helps uh

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