Find the equation of the straight line passing through the point (3,5) which is perpendicular to the line y = 3x + 2
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Answer:
What is the equation of the straight line passing through the point (3,5) which is perpendicular to the line y=3x+2?
What is the equation of the straight line passing through the point (3,5) which is perpendicular to the line y=3x+2?If this line is perpendicular to the line y(1) = 3x + 2, then its slope must be the inverse negative of the reference line y(1). In the general line equation y = mx + b, m is the slope of the line. In the case of y(1), m = 3, so the line we’re looking for, y(2), must have a slope of -1/3. The general equation of all lines with this slope is:
What is the equation of the straight line passing through the point (3,5) which is perpendicular to the line y=3x+2?If this line is perpendicular to the line y(1) = 3x + 2, then its slope must be the inverse negative of the reference line y(1). In the general line equation y = mx + b, m is the slope of the line. In the case of y(1), m = 3, so the line we’re looking for, y(2), must have a slope of -1/3. The general equation of all lines with this slope is:y(unk) = (-1/3)x + b
What is the equation of the straight line passing through the point (3,5) which is perpendicular to the line y=3x+2?If this line is perpendicular to the line y(1) = 3x + 2, then its slope must be the inverse negative of the reference line y(1). In the general line equation y = mx + b, m is the slope of the line. In the case of y(1), m = 3, so the line we’re looking for, y(2), must have a slope of -1/3. The general equation of all lines with this slope is:y(unk) = (-1/3)x + bBut I still have an unknown term, b, to figure out.
What is the equation of the straight line passing through the point (3,5) which is perpendicular to the line y=3x+2?If this line is perpendicular to the line y(1) = 3x + 2, then its slope must be the inverse negative of the reference line y(1). In the general line equation y = mx + b, m is the slope of the line. In the case of y(1), m = 3, so the line we’re looking for, y(2), must have a slope of -1/3. The general equation of all lines with this slope is:y(unk) = (-1/3)x + bBut I still have an unknown term, b, to figure out.I am told that this unknown line y(2) passes through the point (3,5), so the above equation must be true for (3,5). In order to find b, I only need substitute (3,5) for x and y in y(unk) and get the following: 5 = (-1/3)3 + b or 5 = -1 + b which reduces to b = 6. So the line I’m searching for is y(2) = (-1/3)x + 6
Step-by-step explanation:
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Answer:
-1/3x+6
Step-by-step explanation:
i copied the other guy