find the equation of the straight line perpendicular to the line 2x+6y=3 and with y intercept 2 units
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Answer:
Given line is 2x - 3y = 7
(1) ⇒ 3y = 2x - 7 ⇒ y =
3
2
x−
3
7
∴ Slope of (1) is 2/3. The required line is parallel to (1) so its slope is also 2/3 y-intercept of required line = 4
∴ By using y = mx + c form the equation of the required line is y =
3
2
x+4or2x−3y+12=0
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