Question

Find the equation of the straight line perpendicular to the line 2x + 3y=0 and passing through the point of intersection of the lines x + 3y - 1 = 0 and x-2y + 4 = 0. and​

Answer 1

Answer:

3x - 2y + 8 = 0

Step-by-step explanation:

The photo is the answer

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Answer 2

Step-by-step explanation:

m = 3/2

x + 3y = 1

x - 2y = -4

=>. 5y = 5

=> y = 1

=> x = -2

Equation of required line is

y - 1 = 3/2 ( x + 2)