Question

find the equation of the straight line perpendicular to2x-3y is equal to 5and cutting off an intercept 1 on the x-axis​

Answer 1

Answer:

The line perpendicular to 2x - 3y = 5 is 3x +2y+=0

It is given that the line 3x +2y+= 0

cuts off an intercept of 1 on the positive direction of the x-axis.

This means that the line

3x + 2y + 1 = 0 passes through the

point (1,0),

. 3+0+1= 0. 3+0+1= 0

-3

Substituting the value of we get

3x + 2y - 3 = 0 which is equation of the required line

View in app x

Answer 2

Answer:

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