Find the equation of the straight line through the given
point P and having the given slope m if
(a) P(-4, 7); m=-√3
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Answer:
Equation of required line is √3x +y - (7 - 4√3) = 0
Step-by-step explanation:
The eqn of the line is
y - y₁ = m (x - x₁) ↔ Slope point form
y - 7 = -√3 [x - (-4)]
y - 7 = - √3 x - 4√3
√3x +y - (7 - 4√3) = 0
∴ Eqn of required line is √3x +y - (7 - 4√3) = 0
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