Question

Find the equation of the straight line through the point
(3, 2) which makes acute angle 45° with the line
x-2y=3.​

Answer 1

Step-by-step explanation:

slope of the x-2y=3 is 1/2 (m=-A/B)

tan theta =|m1-m2|/1+m1m2

tan(45°)= |1/2-m|/1+1/2m

+-1=1-2m/2+m

2+m=1-2m or -(2+m) =1-2m

3m=-1 or -2-m=1-2m

m=-1/3 or m=3

we know that,

(y-y0) =m(x-x0)

y-2=3(x-3)

y-2=3x-9

3x-y=7

similarly,

y-2=(-1/3)(x-3)

3y-6=-x+3

x+3y=9