Question

Find the equation of the straight line upon which length of the perpendicular from
the origin is 6 and the gradient of this perpendicular is 3/4.

Answer 1

Solution

12x+5y±26=0

The standard equation is mx+c

where m= slope and c=y intercept

here m=

12

5

and c=2

substituting the values we get

y=

12

5

x+2

12y=5x+24

we get,

12y=5x+24is the required answer.

Answer 2

Answer:

12x+5y±26=0

The standard equation is mx+c

where m= slope and c=y intercept

here m=

12

5

and c=2

substituting the values we get

y=

12

5

x+2

12y=5x+24

we get,

12y=5x+24is the required answer.