Find the equation of the straight line which has gradient 3 and which passes through the point (3,1)
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the equation of genral straight line is y = mx+c. where m is gradient and x,y are the passing point
given m = 3
passing points (3,1 )
we have to find constant c
then y= 3x + c
c = y/3x on putting the value we get
c = 1/6
then the equation is y= 3x + 1/6.
given m = 3
passing points (3,1 )
we have to find constant c
then y= 3x + c
c = y/3x on putting the value we get
c = 1/6
then the equation is y= 3x + 1/6.
kholarehman:
i don't think the answer is correct
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