Question

find the equation of the straight line which makes angle 135° with the positive direction of x-axes and passing through(3,-2)​

Answer 1

Answer:

The slope of the line, m = tan (135°) = tan (45°) = -1; as 135° lies in 2nd quadrant and as such tan is negative by ASTC rule.

The line passes through a point (2,-3) and an arbitrary point (x,y).

Slope, m = (y - y1)/(x - x1)

y - y1 = m(x - x1); slope-point form

y + 3 = -1(x - 2)

y + 3 = -x + 2

Hence, equation of the line is

y = -x - 1; slope-intercept form; y = -(x+1)

y + x + 1 = 0; general form

Answer 2

Step-by-step explanation:

Solution

Here,

<br> Hence, the required equation is