Math, asked by abolajiadegunju, 8 months ago

Find the equation of the straight line which passes through the points (-1, 1) and (2, -3)

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Answered by navnathblp
4

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Answered by Anonymous
43

Given :-

A straight line passes through the two points (-1, 1) and (2, -3)

To find :-

The equation of straight line

Solution :-

Inorder to find the required equation of straight line where two coordinates are given through which the given line passes, we use two point form of straight line.

Two point form:

 \boxed{\sf y - y_1 = \dfrac{y_2-y_1}{x_2-x_1}(x-x_1)}

Here,

  • (x1, y1) = (-1, 1)
  • (x2, y2) = (2, -3)
  • (x, y) are variables

By substituting the known values in the two point form equation, we get:

\sf  \implies y - y_1 = \dfrac{y_2-y_1}{x_2-x_1}(x-x_1)

\sf  \implies y - 1= \dfrac{-3-1}{2-(-1)}(x-(-1))

\sf  \implies y - 1= \dfrac{ - 4}{3}(x+1)

\sf  \implies -3(y - 1)= 4(x+1)

\sf  \implies -3y  + 3= 4x+4

\sf  \implies    0 = 4x + 3y + 4 - 3

\sf  \implies    0 = 4x + 3y + 1

Hence this is the required equation of straight line.

Learn More:

Straight lines lesson all formulas

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