find the equation of the straight line which passes through the point (-1,3) and having x-intercepts thrice of y-intercepts
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Answer:
The general equation of a straight line is y=kx+d
So we know 3=k+d
and the y intercept is d (x=0) while the x intercept is at −dk (y=0
).
So d=−3dk
. Combing this we get k=−3 and d=6 or d=0 and k=3
.
3x
intersects both x and y at 0 this works, while 6−3x intersects x and y at 2 and 6 respectively this works too
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