Question

Find the equation of the straight line which passes through the point (2, 3) and
whose intercept on the x-axis is double that on the y-axis,​

Answer 1

Solution :

The point of intersection : ( 2, 3 )

Here , the intercept on the x axis is double the intercept on the y axis .

Let the intercepts on x and y axes be a and b respectively .

=> a = 2b

Slope of the line , m

=> m = a/b = 2 .

Now ,we have obtained the slope of the line and a point lying on the line .

According to the slope intercept form ,

( y - y¹ ) = m ( x - x¹ )

=> y - 3 = 2 ( x - 2 )

=> y - 3 = 2x - 4

=> 2x - y - 1 = 0

This is the required equation of the line .

______________________________

Answer 2

it is given that , intercept on the positive y-axis equal to twice its intercept on the positive x-axis ⇒y=2x

So, now slope of the line will be m=  

x

2x

​  

=2

Thus, Equation will be

(y−3)=2(x−2)⇒2x−y=1

Therefore, Answer is D