Question

Find the equation of the straight line which passes through (4, 5) and is (i) parallel
(ii) perpendicular to the straight line 3x - 2y + 5 = 0.

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Answer 1

answer:The equation of a line perpendicular to 3x + 2y + 5 = 0 is 2x - 3y + λ = 0           i)

The equation of a line perpendicular to 3x + 2y + 5 = 0 is 2x - 3y + λ = 0           i)This passes through the point (3, 4)

The equation of a line perpendicular to 3x + 2y + 5 = 0 is 2x - 3y + λ = 0           i)This passes through the point (3, 4)∴3×2−3×4+λ=0⇒λ=6

The equation of a line perpendicular to 3x + 2y + 5 = 0 is 2x - 3y + λ = 0           i)This passes through the point (3, 4)∴3×2−3×4+λ=0⇒λ=6Putting λ=6 in (i) we get 2x−3y+6=0 which is the required equation

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